4x^2-14x-296=0

Solution for 4x^2-14x-296=0 equation:

4x^2-14x-296=0

a = 4; b = -14; c = -296;
Δ = b2-4ac
Δ = -142-4·4·(-296)
Δ = 4932
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4932}=\sqrt{36*137}=\sqrt{36}*\sqrt{137}=6\sqrt{137}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-14)-6\sqrt{137}}{2*4}=\frac{14-6\sqrt{137}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-14)+6\sqrt{137}}{2*4}=\frac{14+6\sqrt{137}}{8}
$